SQLAlchemy ORM - 使用连接
现在我们有了两个表,我们将了解如何同时在两个表上创建查询。要构建 Customer 和 Invoice 之间的简单隐式连接,我们可以使用 Query.filter() 将它们的相关列等同起来。下面,我们使用此方法一次加载 Customer 和 Invoice 实体 −
from sqlalchemy.orm import sessionmaker Session = sessionmaker(bind = engine) session = Session() for c, i in session.query(Customer, Invoice).filter(Customer.id == Invoice.custid).all(): print ("ID: {} Name: {} Invoice No: {} Amount: {}".format(c.id,c.name, i.invno, i.amount))
SQLAlchemy 发出的 SQL 表达式如下 −
SELECT customers.id AS customers_id, customers.name AS customers_name, customers.address AS customers_address, customers.email AS customers_email, invoices.id AS invoices_id, invoices.custid AS invoices_custid, invoices.invno AS invoices_invno, invoices.amount AS invoices_amount FROM customers, invoices WHERE customers.id = invoices.custid
SQLAlchemy 发出的 SQL 表达式如下 −
ID: 2 Name: Gopal Krishna Invoice No: 10 Amount: 15000 ID: 2 Name: Gopal Krishna Invoice No: 14 Amount: 3850 ID: 3 Name: Govind Pant Invoice No: 3 Amount: 10000 ID: 3 Name: Govind Pant Invoice No: 4 Amount: 5000 ID: 4 Name: Govind Kala Invoice No: 7 Amount: 12000 ID: 4 Name: Govind Kala Invoice No: 8 Amount: 8500 ID: 5 Name: Abdul Rahman Invoice No: 9 Amount: 15000 ID: 5 Name: Abdul Rahman Invoice No: 11 Amount: 6000
实际的 SQL JOIN 语法可以使用 Query.join() 方法轻松实现,如下所示 −
session.query(Customer).join(Invoice).filter(Invoice.amount == 8500).all()
join 的 SQL 表达式将显示在控制台上 −
SELECT customers.id AS customers_id, customers.name AS customers_name, customers.address AS customers_address, customers.email AS customers_email FROM customers JOIN invoices ON customers.id = invoices.custid WHERE invoices.amount = ?
我们可以使用 for 循环迭代结果 −
result = session.query(Customer).join(Invoice).filter(Invoice.amount == 8500) for row in result: for inv in row.invoices: print (row.id, row.name, inv.invno, inv.amount)
使用 8500 作为绑定参数,将显示以下输出 −
4 Govind Kala 8 8500
Query.join() 知道如何连接这些表,因为它们之间只有一个外键。如果没有外键,或者有更多外键,则使用以下形式之一时 Query.join() 效果会更好 −
query.join(Invoice, id == Address.custid) | 明确条件 |
query.join(Customer.invoices) | 从左到右指定关系 |
query.join(Invoice, Customer.invoices) | 相同,具有明确目标 |
query.join('invoices') | 相同,使用string |
同样,outerjoin() 函数可用于实现左外连接。
query.outerjoin(Customer.invoices)
subquery() 方法生成一个 SQL 表达式,表示嵌入在别名中的 SELECT 语句。
from sqlalchemy.sql import func stmt = session.query( Invoice.custid, func.count('*').label('invoice_count') ).group_by(Invoice.custid).subquery()
stmt 对象将包含如下 SQL 语句 −
SELECT invoices.custid, count(:count_1) AS invoice_count FROM invoices GROUP BY invoices.custid
一旦我们有了语句,它就会像一个表构造一样运行。语句上的列可通过名为 c 的属性访问,如以下代码所示 −
for u, count in session.query(Customer, stmt.c.invoice_count).outerjoin(stmt, Customer.id == stmt.c.custid).order_by(Customer.id): print(u.name, count)
上面的 for 循环按名称显示invoices数量,如下所示 −
Arjun Pandit None Gopal Krishna 2 Govind Pant 2 Govind Kala 2 Abdul Rahman 2