Java 并发 - 死锁

死锁描述了两个或多个线程永远阻塞、互相等待的情况。 当多个线程需要相同的锁但以不同的顺序获取锁时，就会发生死锁。 Java 多线程程序可能会遇到死锁情况，因为 synchronized 关键字会导致执行线程在等待与指定对象关联的锁或监视器时阻塞。 这是一个例子。

示例

public class TestThread {
   public static Object Lock1 = new Object();
   public static Object Lock2 = new Object();
   
   public static void main(String args[]) {
      ThreadDemo1 T1 = new ThreadDemo1();
      ThreadDemo2 T2 = new ThreadDemo2();
      T1.start();
      T2.start();
   }
   
   private static class ThreadDemo1 extends Thread {
   
      public void run() {
      
         synchronized (Lock1) {
            System.out.println("Thread 1: Holding lock 1...");

            try {
               Thread.sleep(10);
            } catch (InterruptedException e) {}
            System.out.println("Thread 1: Waiting for lock 2...");

            synchronized (Lock2) {
               System.out.println("Thread 1: Holding lock 1 & 2...");
            }
         }
      }
   }

   private static class ThreadDemo2 extends Thread {
   
      public void run() {
      
         synchronized (Lock2) {
            System.out.println("Thread 2: Holding lock 2...");
            
            try {
               Thread.sleep(10);
            } catch (InterruptedException e) {}
            System.out.println("Thread 2: Waiting for lock 1...");
            
            synchronized (Lock1) {
               System.out.println("Thread 2: Holding lock 1 & 2...");
            }
         }
      }
   } 
}

当您编译并执行上述程序时，您会发现死锁情况，以下是程序产生的输出 −

输出

Thread 1: Holding lock 1...
Thread 2: Holding lock 2...
Thread 1: Waiting for lock 2...
Thread 2: Waiting for lock 1...

上面的程序将永远挂起，因为两个线程都没有到位并等待彼此释放锁，因此您可以通过按 CTRL+C 退出程序。

死锁解决方案示例

让我们更改同一程序的锁定和运行顺序，看看两个线程是否仍在互相等待 −

示例

public class TestThread {
   public static Object Lock1 = new Object();
   public static Object Lock2 = new Object();
   
   public static void main(String args[]) {
      ThreadDemo1 T1 = new ThreadDemo1();
      ThreadDemo2 T2 = new ThreadDemo2();
      T1.start();
      T2.start();
   }
   
   private static class ThreadDemo1 extends Thread {
   
      public void run() {
         
         synchronized (Lock1) {
            System.out.println("Thread 1: Holding lock 1...");
            
            try {
               Thread.sleep(10);
            } catch (InterruptedException e) {}
            System.out.println("Thread 1: Waiting for lock 2...");

            synchronized (Lock2) {
               System.out.println("Thread 1: Holding lock 1 & 2...");
            }
         }
      }
   }

   private static class ThreadDemo2 extends Thread {
      
      public void run() {
         
         synchronized (Lock1) {
            System.out.println("Thread 2: Holding lock 1...");
           
            try {
               Thread.sleep(10);
            } catch (InterruptedException e) {}
            System.out.println("Thread 2: Waiting for lock 2...");

            synchronized (Lock2) {
               System.out.println("Thread 2: Holding lock 1 & 2...");
            }
         }
      }
   } 
}

因此，只需更改锁的顺序即可防止程序陷入死锁情况，并以以下结果完成 −

输出

Thread 1: Holding lock 1...
Thread 1: Waiting for lock 2...
Thread 1: Holding lock 1 & 2...
Thread 2: Holding lock 1...
Thread 2: Waiting for lock 2...
Thread 2: Holding lock 1 & 2...

上面的示例只是为了阐明概念，但是，这是一个复杂的概念，在开发应用程序来处理死锁情况之前，您应该深入研究它。