PHP 和 MySQL - 更新记录示例
PHP 使用 mysqli query() 或 mysql_query() 函数来更新 MySQL 表中的记录。 该函数采用两个参数，成功时返回 TRUE，失败时返回 FALSE。
语法
$mysqli->query($sql,$resultmode)
| Sr.No. | 参数及说明 |
|---|---|
| 1 |
$sql 必需 - 用于更新 MySQL 表中记录的 SQL 查询。 |
| 2 |
$resultmode 可选 - 常量 MYSQLI_USE_RESULT 或 MYSQLI_STORE_RESULT，具体取决于所需的行为。 默认情况下，使用 MYSQLI_STORE_RESULT。 |
Example
Try the following example to update a record in a table −
Copy and paste the following example as mysql_example.php −
<html>
<head>
<title>Updating MySQL Table</title>
</head>
<body>
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = 'root@123';
$dbname = 'TUTORIALS';
$mysqli = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
if($mysqli->connect_errno ) {
printf("Connect failed: %s<br />", $mysqli->connect_error);
exit();
}
printf('Connected successfully.<br />');
if ($mysqli->query('UPDATE tutorials_tbl set tutorial_title = "Learning Java" where tutorial_id = 4')) {
printf("Table tutorials_tbl updated successfully.<br />");
}
if ($mysqli->errno) {
printf("Could not update table: %s<br />", $mysqli->error);
}
$sql = "SELECT tutorial_id, tutorial_title, tutorial_author, submission_date FROM tutorials_tbl";
$result = $mysqli->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
printf("Id: %s, Title: %s, Author: %s, Date: %d <br />",
$row["tutorial_id"],
$row["tutorial_title"],
$row["tutorial_author"],
$row["submission_date"]);
}
} else {
printf('No record found.<br />');
}
mysqli_free_result($result);
$mysqli->close();
?>
</body>
</html>
输出
访问部署在 apache Web 服务器上的 mysql_example.php 并验证输出。 在这里，我们在运行选择脚本之前在表中输入了多条记录。
Connected successfully. Table tutorials_tbl updated successfully. Id: 1, Title: MySQL Tutorial, Author: Mahesh, Date: 2021 Id: 2, Title: HTML Tutorial, Author: Mahesh, Date: 2021 Id: 3, Title: PHP Tutorial, Author: Mahesh, Date: 2021 Id: 4, Title: Learning Java, Author: Mahesh, Date: 2021 Id: 5, Title: Apache Tutorial, Author: Suresh, Date: 2021
