MySQL HAVING 子句
MySQL HAVING 子句
HAVING
子句已添加到 SQL,因为 WHERE
关键字不能与聚合函数一起使用。
HAVING 语法
SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY
column_name(s);
演示数据库
以下是 Northwind 示例数据库中"Customers"表的选择:
CustomerID | CustomerName | ContactName | Address | City | PostalCode | Country |
---|---|---|---|---|---|---|
1 |
Alfreds Futterkiste | Maria Anders | Obere Str. 57 | Berlin | 12209 | Germany |
2 | Ana Trujillo Emparedados y helados | Ana Trujillo | Avda. de la Constitución 2222 | México D.F. | 05021 | Mexico |
3 | Antonio Moreno Taquería | Antonio Moreno | Mataderos 2312 | México D.F. | 05023 | Mexico |
4 |
Around the Horn | Thomas Hardy | 120 Hanover Sq. | London | WA1 1DP | UK |
5 | Berglunds snabbköp | Christina Berglund | Berguvsvägen 8 | Luleå | S-958 22 | Sweden |
MySQL HAVING 示例
以下 SQL 语句列出了每个地区的客户数量。 仅包括拥有 5 个以上客户的地区:
实例
SELECT COUNT(CustomerID), Country
FROM Customers
GROUP BY Country
HAVING COUNT(CustomerID) > 5;
亲自试一试 »
以下 SQL 语句列出了每个地区的客户数量,从高到低排序(仅包括客户超过 5 个的地区):
实例
SELECT COUNT(CustomerID), Country
FROM Customers
GROUP BY Country
HAVING COUNT(CustomerID)
> 5
ORDER BY COUNT(CustomerID) DESC;
亲自试一试 »
演示数据库
以下是 Northwind 示例数据库中"Orders"表的选择:
OrderID | CustomerID | EmployeeID | OrderDate | ShipperID |
---|---|---|---|---|
10248 | 90 | 5 | 1996-07-04 | 3 |
10249 | 81 | 6 | 1996-07-05 | 1 |
10250 | 34 | 4 | 1996-07-08 | 2 |
以及从"Employees"表中选择的内容:
EmployeeID | LastName | FirstName | BirthDate | Photo | Notes |
---|---|---|---|---|---|
1 | Davolio | Nancy | 1968-12-08 | EmpID1.pic | Education includes a BA.... |
2 | Fuller | Andrew | 1952-02-19 | EmpID2.pic | Andrew received his BTS.... |
3 | Leverling | Janet | 1963-08-30 | EmpID3.pic | Janet has a BS degree.... |
更多 HAVING 示例
以下 SQL 语句列出了注册超过 10 个订单的员工:
实例
SELECT Employees.LastName, COUNT(Orders.OrderID) AS NumberOfOrders
FROM
(Orders
INNER JOIN Employees ON Orders.EmployeeID = Employees.EmployeeID)
GROUP BY LastName
HAVING COUNT(Orders.OrderID) > 10;
亲自试一试 »
以下 SQL 语句列出员工"Davolio"或"Fuller"是否已注册超过 25 个订单:
实例
SELECT Employees.LastName, COUNT(Orders.OrderID) AS NumberOfOrders
FROM Orders
INNER JOIN Employees ON Orders.EmployeeID = Employees.EmployeeID
WHERE LastName = 'Davolio' OR LastName = 'Fuller'
GROUP BY LastName
HAVING
COUNT(Orders.OrderID) > 25;
亲自试一试 »