MySQL 查询选择一周前的行?
mysqlmysqli database
为此，您可以使用 DATEDIFF() 函数。当前日期时间如下 −
mysql> select now(); +---------------------+ | now() | +---------------------+ | 2019-06-09 19:15:56 | +---------------------+ 1 row in set (0.00 sec)
首先我们创建一个表 −
mysql> create table DemoTable -> ( -> ShippingDate datetime -> ); Query OK, 0 rows affected (0.66 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable values('2019-06-01');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable values('2019-06-02');
Query OK, 1 row affected (0.21 sec)
mysql> insert into DemoTable values('2019-06-14');
Query OK, 1 row affected (0.18 sec)
mysql> insert into DemoTable values('2019-05-21');
Query OK, 1 row affected (0.24 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable;
输出
+---------------------+ | ShippingDate | +---------------------+ | 2019-06-01 00:00:00 | | 2019-06-02 00:00:00 | | 2019-06-14 00:00:00 | | 2019-05-21 00:00:00 | +---------------------+ 4 rows in set (0.00 sec)
以下是选择一周前行的查询。假设当前日期是"2019-06-09"。因此，将选择一周前(即"2019-06-02"之前的行)的行 −
mysql> select *from DemoTable where DATEDIFF(now(),ShippingDate) > 7;
输出
+---------------------+ | ShippingDate | +---------------------+ | 2019-06-01 00:00:00 | | 2019-05-21 00:00:00 | +---------------------+ 2 rows in set (0.00 sec)
