MySQL 查询选择名称为 records 的列中最后一个空格左侧的所有内容
mysqlmysqli database
为此，您可以使用 LEFT()。让我们首先创建一个表 −
mysql> create table DemoTable1939 ( FullName varchar(20) ); Query OK, 0 rows affected (0.00 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable1939 values('Adam Smith');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1939 values('Robert Downey, Jr.');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1939 values('Sylvester Stallone');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1939 values('Chris Hemsworth');
Query OK, 1 row affected (0.00 sec)
使用 select 语句显示表中的所有记录 −
mysql> select * from DemoTable1939;
这将产生以下输出 −
+--------------------+ | FullName | +--------------------+ | Adam Smith | | Robert Downey, Jr. | | Sylvester Stallone | | Chris Hemsworth | +--------------------+ 4 rows in set (0.00 sec)
以下查询用于选择最后一个空格左侧的所有内容
mysql> select
LEFT(FullName, LENGTH(FullName) - LOCATE(' ', REVERSE(FullName))+1)
from DemoTable1939;
这将产生以下输出 −
+---------------------------------------------------------------------+
| LEFT(FullName, LENGTH(FullName) - LOCATE(' ', REVERSE(FullName))+1) |
+---------------------------------------------------------------------+
| Adam |
| Robert Downey, |
| Sylvester |
| Chris |
+---------------------------------------------------------------------+
4 rows in set (0.00 sec)
