MySQL 查询返回日期时间超过 1 周的所有记录
mysqlmysqli database
要获取超过 1 周的日期，您可以使用以下语法−
select *from yourTableName where yourColumnName < now() - interval 1 week;
为了理解上述概念，让我们创建一个表。创建表的查询如下 −
mysql> create table DatesOfOneWeek −> ( −> ArrivalTime datetime −> ); Query OK, 0 rows affected (0.87 sec)
在表中插入一些记录 −
mysql> insert into DatesOfOneWeek values(date_add(now(),interval 2 week));
Query OK, 1 row affected (0.11 sec)
mysql> insert into DatesOfOneWeek values('2018-11-04');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DatesOfOneWeek values('2018-11-25');
Query OK, 1 row affected (0.11 sec)
mysql> insert into DatesOfOneWeek values(date_add(now(),interval -1 week));
Query OK, 1 row affected (0.14 sec)
mysql> insert into DatesOfOneWeek values(date_add(now(),interval 1 week));
Query OK, 1 row affected (0.11 sec)
让我们检查一下上面插入的记录是否存在。显示表中所有记录的查询如下 −
mysql> select *from DatesOfOneWeek;
以下是输出 −
+---------------------+ | ArrivalTime | +---------------------+ | 2018-12-20 18:11:02 | | 2018-11-04 00:00:00 | | 2018-11-25 00:00:00 | | 2018-11-29 18:11:40 | | 2018-12-13 18:11:46 | +---------------------+ 5 rows in set (0.00 sec)
这是 MySQL 查询，用于获取过去的日期，即 1 周之前的所有日期 −
mysql> select *from DatesOfOneWeek where ArrivalTime < now() - interval 1 week;
以下是输出 −
+---------------------+ | ArrivalTime | +---------------------+ | 2018-11-04 00:00:00 | | 2018-11-25 00:00:00 | | 2018-11-29 18:11:40 | +---------------------+ 3 rows in set (0.00 sec)
