如何在 MySQL 中选取多列中有一列等于某个值的行?
mysqlmysqli database
为此，您可以使用多个 OR。让我们首先创建一个表 −
mysql> create table DemoTable ( Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, FirstName varchar(10), LastName varchar(10), Age int, CountryName varchar(10) ); Query OK, 0 rows affected (0.58 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable(FirstName,LastName,Age,CountryName)
values('John','Smith',21,'US');
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable(FirstName,LastName,Age,CountryName)
values('Carol','Taylor',22,'AUS');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable(FirstName,LastName,Age,CountryName)
values('David','Miller',19,'UK');
Query OK, 1 row affected (0.16 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable;
输出
+----+-----------+----------+------+-------------+ | Id | FirstName | LastName | Age | CountryName | +----+-----------+----------+------+-------------+ | 1 | John | Smith | 21 | US | | 2 | Carol | Taylor | 22 | AUS | | 3 | David | Miller | 19 | UK | +----+-----------+----------+------+-------------+ 3 rows in set (0.00 sec)
以下查询用于选择其中某一列等于某个值的行 −
mysql> select *from DemoTable where FirstName="Carol" OR Age=22 OR CountryName="AUS";
输出
+----+-----------+----------+------+-------------+ | Id | FirstName | LastName | Age | CountryName | +----+-----------+----------+------+-------------+ | 2 | Carol | Taylor | 22 | AUS | +----+-----------+----------+------+-------------+ 1 row in set (0.00 sec)
