如何使用 MySQL LIKE 从第一个表创建新表?
mysqlmysqli database
首先我们创建一个表 −
mysql> create table DemoTable1 ( EmployeeId int NOT NULL AUTO_INCREMENT PRIMARY KEY, EmployeeName varchar(50) ); Query OK, 0 rows affected (0.48 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable1(EmployeeName) values('Tom');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable1(EmployeeName) values('Mike');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable1(EmployeeName) values('Emma');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable1(EmployeeName) values('Sam');
Query OK, 1 row affected (0.10 sec)
使用 select 语句显示表中的所有记录:
mysql> select *from DemoTable1;
这将产生以下输出 −
+------------+--------------+ | EmployeeId | EmployeeName | +------------+--------------+ | 1 | Tom | | 2 | Mike | | 3 | Emma | | 4 | Sam | +------------+--------------+ 4 rows in set (0.00 sec)
以下是在 MySQL 中使用 LIKE 从另一个表创建新表的查询 −
mysql> create table DemoTable2 LIKE DemoTable1; Query OK, 0 rows affected (0.55 sec)
让我们检查一下表的描述 −
mysql> desc DemoTable2;
这将产生以下输出 −
+--------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------+-------------+------+-----+---------+----------------+ | EmployeeId | int(11) | NO | PRI | NULL | auto_increment | | EmployeeName | varchar(50) | YES | | NULL | | +--------------+-------------+------+-----+---------+----------------+ 2 rows in set (0.00 sec)
