在 MySQL 中从具有不同 ID 的同一张表中获取具有共同值的行
mysqlmysqli database
为此，您可以使用 GROUP BY HAVING 子句。让我们首先创建一个表 −
mysql> create table DemoTable1467 -> ( -> Id int, -> Name varchar(20) -> ); Query OK, 0 rows affected (0.64 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable1467 values(100,'Chris'); Query OK, 1 row affected (0.18 sec) mysql> insert into DemoTable1467 values(110,'David'); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable1467 values(120,'Mike'); Query OK, 1 row affected (0.15 sec) mysql> insert into DemoTable1467 values(100,'Chris'); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable1467 values(130,'Carol'); Query OK, 1 row affected (0.17 sec) mysql> insert into DemoTable1467 values(100,'Chris'); Query OK, 1 row affected (0.20 sec)
使用 select 语句显示表中的所有记录 −
mysql> select * from DemoTable1467;
这将产生以下输出 −
+------+-------+ | Id | Name | +------+-------+ | 100 | Chris | | 110 | David | | 120 | Mike | | 100 | Chris | | 130 | Carol | | 100 | Chris | +------+-------+ 6 rows in set (0.00 sec)
以下查询用于从同一张表中获取具有不同 ID 的共同值的行 −
mysql> select Id,Name,count(*) as IdCount from DemoTable1467 -> group by Id -> having IdCount > 2;
这将产生以下输出 −
+------+-------+---------+ | Id | Name | IdCount | +------+-------+---------+ | 100 | Chris | 3 | +------+-------+---------+ 1 row in set (0.00 sec)
