C++ 程序将八进制数转换为二进制数
c++programmingserver side programming
在计算机系统中，二进制数以二进制数字系统表示，而八进制数以八进制数字系统表示。二进制数以 2 为基数，而八进制数以 8 为基数。
二进制数及其对应的八进制数的示例如下 −
| 二进制数 | 八进制数 |
|---|---|
| 01101 | 15 |
| 00101 | 5 |
| 10110 | 26 |
| 01010 | 12 |
将八进制数转换为二进制的程序如下 −
示例
#include <iostream>
#include <cmath>
using namespace std;
int OctalToBinary(int octalNum) {
int decimalNum = 0, binaryNum = 0, count = 0;
while(octalNum != 0) {
decimalNum += (octalNum%10) * pow(8,count);
++count;
octalNum/=10;
}
count = 1;
while (decimalNum != 0) {
binaryNum += (decimalNum % 2) * count;
decimalNum /= 2;
count *= 10;
}
return binaryNum;
}
int main() {
int octalNum = 33;
cout <<"Octal to Binary"<<endl;
cout<<"Octal number: "<<octalNum<<endl;
cout<<"Binary number: "<<OctalToBinary(octalNum)<<endl;
return 0;
}
输出
上述程序的输出如下 −
Octal to Binary Octal number: 33 Binary number: 11011
在给定的程序中，函数 OctalToBinary() 将给定的八进制数转换为二进制数。这是通过首先将八进制数转换为十进制数，然后将十进制数转换为二进制数来实现的。这在以下代码片段中可见 −
int OctalToBinary(int octalNum) {
int decimalNum = 0, binaryNum = 0, count = 0;
while(octalNum != 0) {
decimalNum += (octalNum%10) * pow(8,count);
++count;
octalNum/=10;
}
count = 1;
while (decimalNum != 0) {
binaryNum += (decimalNum % 2) * count;
decimalNum /= 2;
count *= 10;
}
return binaryNum;
}
In the function main(), the octal number is given. Then its corresponding binary number is calculated by calling OctalToBinary(). This is shown below −
int main() {
int octalNum = 33;
cout <<"Octal to Binary"<<endl;
cout<<"Octal number: "<<octalNum<<endl;
cout<<"Binary number: "<<OctalToBinary(octalNum)<<endl;
return 0;
}
