C++ Unordered_set 库 - bucket_count
描述
它返回 unordered_set 容器中的桶数。
声明
以下是 std::unordered_set::bucket_count 的声明。
C++11
size_type bucket_count() const noexcept;
参数
none
返回值
它返回 unordered_set 容器中的桶数。
异常
如果任何元素比较对象抛出异常，则抛出异常。
请注意，无效的参数会导致未定义的行为。
时间复杂度
固定的时间。
示例
以下示例显示了 std::unordered_set::bucket_count 的用法。
#include <iostream>
#include <string>
#include <unordered_set>
int main () {
std::unordered_set<std::string> myset =
{"sai","ram","krishna","prasad","mammahe","tutorials","point","com"};
unsigned n = myset.bucket_count();
std::cout << "myset has " << n << " buckets.\n";
for (unsigned i = 0; i < n; ++i) {
std::cout << "bucket #" << i << " contains:";
for (auto it = myset.begin(i); it!=myset.end(i); ++it)
std::cout << " " << *it;
std::cout << "\n";
}
return 0;
}
让我们编译并运行上面的程序，这将产生以下结果 −
myset has 11 buckets. bucket #0 contains: bucket #1 contains: bucket #2 contains: tutorials sai bucket #3 contains: krishna ram bucket #4 contains: bucket #5 contains: bucket #6 contains: mammahe prasad bucket #7 contains: bucket #8 contains: com bucket #9 contains: point bucket #10 contains:
