如何在 Java 中忽略 JSON 对象的多个属性?
javajsonobject oriented programmingprogramming
@JsonIgnorePropertiesJackson 注释可用于指定要忽略的类的属性列表或字段。@JsonIgnoreProperties 注释可以放在类声明上方，而不是放在要忽略的单个属性或字段上方。
语法
@Target(value={ANNOTATION_TYPE,TYPE,METHOD,CONSTRUCTOR,FIELD})
@Retention(value=RUNTIME)
public @interface JsonIgnoreProperties
示例
import java.io.*;
import com.fasterxml.jackson.annotation.*;
import com.fasterxml.jackson.databind.*;
public class JsonIgnorePropertiesTest {
public static void main(String[] args) throws IOException {
Customer customer = new Customer("120", "Ravi", "Hyderabad");
System.out.println(customer);
ObjectMapper mapper = new ObjectMapper();
String jsonString = mapper.writeValueAsString(customer);
System.out.println("JSON: " + jsonString);
System.out.println("---------");
jsonString = "{\"id\":\"130\",\"name\":\"Rahul\", \"address\":\"Mumbai\"}";
System.out.println("JSON: " + jsonString);
customer = mapper.readValue(jsonString, Customer.class);
System.out.println(customer);
}
}
// Customer class
@JsonIgnoreProperties({"id", "address"}) class Customer {
private String id;
private String name;
private String address;
public Customer() {
}
public Customer(String id, String name, String address) {
this.id = id;
this.name = name;
this.address = address;
}
public String getId() {
return id;
}
public String getName() {
return name;
}
public String getAddress() {
return address;
}
@Override
public String toString() {
return "Customer [id=" + id + ", name=" + name + ", address=" + address + "]";
}
}
输出
Customer [id=120, name=Ravi, address=Hyderabad]
JSON: {"name":"Ravi"}
---------
JSON: {"id":"130","name":"Rahul", "address":"Mumbai"}
Customer [id=null, name=Rahul, address=null]
