C++ 程序实现三叉树
c++server side programmingprogramming
三叉树是一种树形数据结构，其中每个节点最多有三个子节点，通常表示为"左"、"中"和"右"。在此树中，具有子节点的节点是父节点，子节点可能包含对其父节点的引用。这是一个 C++ 程序，用于实现三叉树和树的遍历。
算法
Begin Declare function insert(struct nod** root, char *w) if (!(*root)) then *root = newnod(*w); if ((*w) < (*root)->d) then insert(&( (*root)->l ), w); else if ((*w) > (*root)->d) then insert(&( (*root)->r ), w); else if (*(w+1)) insert(&( (*root)->eq ), w+1); else (*root)->EndOfString = 1; End.
对于树的遍历:
Begin Declare function traverseTTtil(struct nod* root, char* buffer, int depth) if (root) then traverseTTtil(root->l, buffer, depth) buffer[depth] = root->d if (root->EndOfString) then buffer[depth+1] = '\0' print the value of buffer. traverseTTtil(root->eq, buffer, depth + 1); traverseTTtil(root->r, buffer, depth); End.
示例
#include<stdlib.h>
#include<iostream>
using namespace std;
struct nod {
char d;
unsigned End.
fString: 1;
struct nod *l, *eq, *r;
}*t = NULL;
struct nod* newnod(char d) {
t = new nod;
t->d = d;
t->End.
fString = 0;
t->l = t->eq = t->r = NULL;
return t;
}
void insert(struct nod** root, char *w) {
if (!(*root))
*root = newnod(*w);
if ((*w) < (*root)->d)
insert(&( (*root)->l ), w);
else if ((*w) > (*root)->d)
insert(&( (*root)->r ), w);
else {
if (*(w+1))
insert(&( (*root)->eq ), w+1);
else
(*root)->End.
fString = 1;
}
}
void traverseTTtil(struct nod* root, char* buffer, int depth) {
if (root) {
traverseTTtil(root->l, buffer, depth);
buffer[depth] = root->d;
if (root->End. String) {
buffer[depth+1] = '\0';
cout<<buffer<<endl;
}
traverseTTtil(root->eq, buffer, depth + 1);
traverseTTtil(root->r, buffer, depth);
}
}
void traverseTT(struct nod* root) {
char buffer[50];
traverseTTtil(root, buffer, 0);
}
int main() {
struct nod *root = NULL;
insert(&root, "mat");
insert(&root, "bat");
insert(&root, "hat");
insert(&root, "rat");
cout<<"以下是三叉树的遍历\n";
traverseTT(root);
}
输出
以下是三叉树的遍历 bat hat mat rat
