在 Java 中检查两个 HashMap 是否相等
java 8object oriented programmingprogramming
要检查两个 HashMap 是否相等，请使用 equals() 方法。
让我们首先创建第一个 HashMap −
// 创建哈希图 1
HashMap hm1 = new HashMap();
hm1.put("Shirts", new Integer(700));
hm1.put("Trousers", new Integer(600));
hm1.put("Jeans", new Integer(1200));
hm1.put("Android TV", new Integer(450));
hm1.put("Air Purifiers", new Integer(300));
hm1.put("Food Processors", new Integer(950));
现在让我们创建第二个 HashMap −
HashMap hm2 = new HashMap();
hm2.put("Shirts", new Integer(700));
hm2.put("Trousers", new Integer(600));
hm2.put("Jeans", new Integer(1200));
hm2.put("Android TV", new Integer(450));
hm2.put("Air Purifiers", new Integer(300));
hm2.put("Food Processors", new Integer(950));
要检查两个 HashMap 是否相等，请使用 equals() 方法，如下所示 −
hm1.equals(hm2)
以下是检查两个 HashMap 是否相等的示例 −
示例
import java.util.*;
public class Demo {
public static void main(String args[]) {
// 创建哈希图 1
HashMap hm1 = new HashMap();
hm1.put("Shirts", new Integer(700));
hm1.put("Trousers", new Integer(600));
hm1.put("Jeans", new Integer(1200));
hm1.put("Android TV", new Integer(450));
hm1.put("Air Purifiers", new Integer(300));
hm1.put("Food Processors", new Integer(950));
System.out.println("Map 1 = "+hm1);
// 创建哈希图 2
HashMap hm2 = new HashMap();
hm2.put("Shirts", new Integer(700));
hm2.put("Trousers", new Integer(600));
hm2.put("Jeans", new Integer(1200));
hm2.put("Android TV", new Integer(450));
hm2.put("Air Purifiers", new Integer(300));
hm2.put("Food Processors", new Integer(950));
System.out.println("Map 2 = "+hm2);
System.out.println("Map 1 is equal to Map 2? "+hm1.equals(hm2));
}
}
输出
Map 1 = {Shirts=700, Food Processors=950, Air Purifiers=300, Jeans=1200, Android TV=450, Trousers=600}
Map 2 = {Shirts=700, Food Processors=950, Air Purifiers=300, Jeans=1200, Android TV=450, Trousers=600}
Map 1 is equal to Map 2? true
