在 C# 中检查 HybridDictionary 中是否有特定键
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要检查 HybridDictionary 中是否有指定键,代码如下 −
示例
using System; using System.Collections; using System.Collections.Specialized; public class Demo { public static void Main(){ HybridDictionary dict = new HybridDictionary(5); dict.Add("A", "AB"); dict.Add("B", "BC"); dict.Add("C", "DE"); dict.Add("D", "FG"); dict.Add("E", "HI"); Console.WriteLine("Key/Value pairs..."); foreach(DictionaryEntry d in dict) Console.WriteLine("Key = "+d.Key + ", Value = " + d.Value); Console.WriteLine("Does HybridDictionary contains the key C? = "+dict.Contains("C")); } }
输出
这将产生以下输出 −
Key/Value pairs... Key = A, Value = AB Key = B, Value = BC Key = C, Value = DE Key = D, Value = FG Key = E, Value = HI Does HybridDictionary contains the key C? = True
示例
现在让我们看另一个例子 −
using System; using System.Collections; using System.Collections.Specialized; public class Demo { public static void Main(){ HybridDictionary dict1 = new HybridDictionary(); dict1.Add("A", "Books"); dict1.Add("B", "Electronics"); dict1.Add("C", "Smart Wearables"); dict1.Add("D", "Pet Supplies"); dict1.Add("E", "Clothing"); dict1.Add("F", "Footwear"); Console.WriteLine("HybridDictionary1 elements..."); foreach(DictionaryEntry d in dict1){ Console.WriteLine(d.Key + " " + d.Value); } Console.WriteLine("Count of Key/value pairs in Dictionary1 = "+dict1.Count); HybridDictionary dict2 = new HybridDictionary(); dict2.Add("1", "One"); dict2.Add("2", "Two"); dict2.Add("3", "Three"); dict2.Add("4", "Four"); dict2.Add("5", "Five"); dict2.Add("6", "Six"); Console.WriteLine("
HybridDictionary2 elements..."); foreach(DictionaryEntry d in dict2){ Console.WriteLine(d.Key + " " + d.Value); } Console.WriteLine("Count of Key/value pairs in Dictionary2 = "+dict1.Count); Console.WriteLine("Does HybridDictionary2 contains the key 10? = "+dict2.Contains(10)); dict2.Clear(); Console.WriteLine("Count of Key/value pairs in Dictionary2 (Updated) = "+dict2.Count); } }
输出
这将产生以下输出 −
HybridDictionary1 elements... A Books B Electronics C Smart Wearables D Pet Supplies E Clothing F Footwear Count of Key/value pairs in Dictionary1 = 6 HybridDictionary2 elements... 1 One 2 Two 3 Three 4 Four 5 Five 6 Six Count of Key/value pairs in Dictionary2 = 6 Does HybridDictionary2 contains the key 10? = False Count of Key/value pairs in Dictionary2 (Updated) = 0