Java 中的 ByteBuffer equals() 方法
java 8object oriented programmingprogramming
可以使用 java.nio.ByteBuffer 类中的 equals() 方法检查两个缓冲区是否相等。如果两个缓冲区具有相同类型的元素、相同数量的元素和相同的元素序列，则它们相等。如果缓冲区相等，则方法 equals() 返回 true，否则返回 false。
下面给出了一个演示此操作的程序 −
示例
import java.nio.*;
import java.util.*;
public class Demo {
public static void main(String[] args) {
int n = 5;
try {
ByteBuffer buffer1 = ByteBuffer.allocate(n);
buffer1.put((byte)1);
buffer1.put((byte)2);
buffer1.put((byte)3);
buffer1.put((byte)4);
buffer1.put((byte)5);
buffer1.rewind();
System.out.println("The first ByteBuffer is: " + Arrays.toString(buffer1.array()));
ByteBuffer buffer2 = ByteBuffer.allocate(n);
buffer2.put((byte)1);
buffer2.put((byte)2);
buffer2.put((byte)3);
buffer2.put((byte)4);
buffer2.put((byte)5);
buffer2.rewind();
System.out.println("The second ByteBuffer is: " + Arrays.toString(buffer2.array()));
boolean flag = buffer1.equals(buffer2);
if (flag)
System.out.println("
Both the buffers are equal");
else
System.out.println("
Both the buffers are not equal");
} catch (IllegalArgumentException e) {
System.out.println("Error!!! IllegalArgumentException");
} catch (ReadOnlyBufferException e){
System.out.println("Error!!! ReadOnlyBufferException");
}
}
}
输出
The first ByteBuffer is: [1, 2, 3, 4, 5] The second ByteBuffer is: [1, 2, 3, 4, 5] Both the buffers are equal
