Java 中的 ByteBuffer compareTo() 方法
java 8object oriented programmingprogramming
可以使用 java.nio.ByteBuffer 类中的 compareTo() 方法将一个缓冲区与另一个缓冲区进行比较。如果缓冲区小于给定的缓冲区，则此方法返回负整数；如果缓冲区等于给定的缓冲区，则返回零；如果缓冲区大于给定的缓冲区，则返回正整数。
下面给出了一个演示此操作的程序 −
示例
import java.nio.*;
import java.util.*;
public class Demo {
public static void main(String[] args) {
int n = 5;
try {
ByteBuffer buffer1 = ByteBuffer.allocate(n);
buffer1.put((byte)1);
buffer1.put((byte)2);
buffer1.put((byte)3);
buffer1.put((byte)4);
buffer1.put((byte)5);
buffer1.rewind();
System.out.println("The first ByteBuffer is: " + Arrays.toString(buffer1.array()));
ByteBuffer buffer2 = ByteBuffer.allocate(n);
buffer2.put((byte)1);
buffer2.put((byte)2);
buffer2.put((byte)3);
buffer2.put((byte)4);
buffer2.put((byte)5);
buffer2.rewind();
System.out.println("The second ByteBuffer is: " + Arrays.toString(buffer2.array()));
int val = buffer1.compareTo(buffer2);
if (val == 0)
System.out.println("
Both the buffers are lexicographically equal");
else if (val > 0)
System.out.println("
The first buffer is lexicographically greater than the second buffer");
else
System.out.println("
The second buffer is lexicographically greater than the first buffer");
} catch (IllegalArgumentException e) {
System.out.println("Error!!! IllegalArgumentException");
} catch (ReadOnlyBufferException e) {
System.out.println("Error!!! ReadOnlyBufferException");
}
}
}
输出
The first ByteBuffer is: [1, 2, 3, 4, 5] The second ByteBuffer is: [1, 2, 3, 4, 5] Both the buffers are lexicographically equal
