Prototype - hasClassName() 方法
此方法检查元素是否具有给定的 CSS className。
语法
element.hasClassName( className );
返回值
如果元素具有给定的类名，则返回 true，否则返回 false。
示例
<html>
<head>
<title>Prototype examples</title>
<script type = "text/javascript" src = "/javascript/prototype.js"></script>
<script>
function showResult() {
if( $('grandfather').hasClassName("test") ) {
alert("Grandfather has CSS test class.");
}
if( $('father').hasClassName("test") ) {
alert("Father has CSS test class.");
}
if( $('kid').hasClassName("test") ) {
alert("Kid has CSS test class.");
}
}
</script>
<style>
.test {
font-size: 12px;
margin-left: 1em;
}
</style>
</head>
<body>
<p>单击按钮查看结果。</p>
<div id = "grandfather" class = "test">This is grand father
<div id = "father"> This is father.
<div id = "kid" class = "test">This is kid</div>
</div>
</div>
<br />
<input type = "button" value = "showResult" onclick = "showResult();"/>
</body>
</html>
prototype_element_object.html
