"ALL"、"ANY"、"SOME"、"IN"运算符在 MySQL 子查询中有何用途?

mysqlmysqli database更新于 2024/3/8 14:13:00

‘ALL’、‘ANY’、’SOME’、’IN’ 运算符将值与子查询返回的每个值进行比较。所有这些运算符都必须跟在比较运算符后面。在 MySQL 子查询中使用这些运算符的语法如下 −

使用 ‘ALL’ 的语法

Operand comparison_operator ALL (subquery)

使用‘ANY’的语法

Operand comparison_operator ANY (subquery)

使用‘SOME’的语法

Operand comparison_operator SOME (subquery)

使用‘IN’的语法

Operand comparison_operator IN (subquery)

示例

我们使用下表中的数据来说明如何在子查询中使用‘ALL’、‘ANY’、’SOME’、’IN’运算符。

mysql> Select * from Customers;
+-------------+----------+
| Customer_Id | Name     |
+-------------+----------+
|           1 | Rahul    |
|           2 | Yashpal  |
|           3 | Gaurav   |
|           4 | Virender |
+-------------+----------+
4 rows in set (0.00 sec)

mysql> Select * from Reservations;
+------+-------------+------------+
| ID   | Customer_id | Day        |
+------+-------------+------------+
|    1 |           1 | 2017-12-30 |
|    2 |           2 | 2017-12-28 |
|    3 |           2 | 2017-12-29 |
|    4 |           1 | 2017-12-25 |
|    5 |           3 | 2017-12-26 |
+------+-------------+------------+
5 rows in set (0.00 sec)

以下查询使用‘ALL’运算符和子查询,并在比较子查询返回的所有值后返回结果。

mysql> SELECT customer_id from Customers WHERE customer_id <> ALL(Select customer_id from reservations);
+-------------+
| customer_id |
+-------------+
|           4 |
+-------------+
1 row in set (0.00 sec)

以下查询将‘ANY’运算符与子查询结合使用,并在比较子查询返回的所有值后返回结果。

mysql> SELECT customer_id from customers WHERE customer_id = ANY(Select customer_id from reservations);
+-------------+
| customer_id |
+-------------+
|           1 |
|           2 |
|           3 |
+-------------+
3 rows in set (0.00 sec)

以下查询使用‘SOME’运算符和子查询,并在比较子查询返回的所有值后返回结果。

mysql> SELECT customer_id from customers WHERE customer_id = Some(Select customer_id from reservations);
+-------------+
| customer_id |
+-------------+
|           1 |
|           2 |
|           3 |
+-------------+
3 rows in set (0.00 sec)

以下查询使用‘IN’运算符和子查询,并在比较子查询返回的所有值后返回结果。

mysql> SELECT customer_id from customers WHERE customer_id IN (Select customer_id from reservations);
+-------------+
| customer_id |
+-------------+
|           1 |
|           2 |
|           3 |
+-------------+
3 rows in set (0.00 sec)

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