使用 MySQL ORDER BY 首先设置某个值?
mysqlmysqli database更新于 2023/11/26 23:57:00
首先我们创建一个表 −
mysql> create table DemoTable -> ( -> Number int -> ); Query OK, 0 rows affected (0.57 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable values(10); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable values(20); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable values(12); Query OK, 1 row affected (0.22 sec) mysql> insert into DemoTable values(14); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable values(19); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable values(45); Query OK, 1 row affected (0.16 sec) mysql> insert into DemoTable values(56); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable values(103); Query OK, 1 row affected (0.17 sec) mysql> insert into DemoTable values(87); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable values(98); Query OK, 1 row affected (0.12 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable;
输出
这将产生以下输出 −
+--------+ | Number | +--------+ | 10 | | 20 | | 12 | | 14 | | 19 | | 45 | | 56 | | 103 | | 87 | | 98 | +--------+ 10 rows in set (0.00 sec)
以下是使用 ORDER BY 对某个值进行排序的查询 −
mysql− select *from DemoTable order by (Number=45) DESC,Number;
输出
这将产生以下输出 −
+--------+ | Number | +--------+ | 45 | | 10 | | 12 | | 14 | | 19 | | 20 | | 56 | | 87 | | 98 | | 103 | +--------+ 10 rows in set (0.00 sec)
