执行 MySQL ORDER BY 关键字匹配?
mysqlmysqli database
为此，让我们创建一个表，插入一些值并使用 ORDER BY CASE。让我们首先创建一个表 −
mysql> create table DemoTable602 (GameName text); Query OK, 0 rows affected (0.55 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable602 values('Candy cash game');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable602 values('Pubg');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable602 values('cash Candy game');
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable602 values('subway');
Query OK, 1 row affected (0.14 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable602;
这将产生以下输出 −
+-----------------+ | GameName | +-----------------+ | Candy cash game | | Pubg | | cash Candy game | | subway | +-----------------+ 4 rows in set (0.00 sec)
以下是执行 MySQL ORDER BY 关键字匹配的查询 −
mysql> select *from DemoTable602 order by CASE WHEN instr(GameName, 'Candy') = 0 then 1 else 0 end, instr(GameName, 'cash') desc;
这将产生以下输出 −
+-----------------+ | GameName | +-----------------+ | Candy cash game | | cash Candy game | | Pubg | | subway | +-----------------+ 4 rows in set (0.00 sec)
