Java 中的 FloatBuffer compareTo() 方法
java 8object oriented programmingprogramming
可以使用 java.nio.FloatBuffer 类中的 compareTo() 方法将一个缓冲区与另一个缓冲区进行比较。如果缓冲区小于给定的缓冲区，则此方法返回负整数;如果缓冲区等于给定的缓冲区，则返回零;如果缓冲区大于给定的缓冲区，则返回正整数。
下面给出了一个演示此操作的程序 −
示例
import java.nio.*;
import java.util.*;
public class Demo {
public static void main(String[] args) {
int n = 5;
try {
FloatBuffer buffer1 = FloatBuffer.allocate(n);
buffer1.put(4.5F);
buffer1.put(1.2F);
buffer1.put(3.9F);
buffer1.put(7.5F);
buffer1.put(5.8F);
buffer1.rewind();
System.out.println("The first FloatBuffer is: " + Arrays.toString(buffer1.array()));
FloatBuffer buffer2 = FloatBuffer.allocate(n);
buffer2.put(4.5F);
buffer2.put(1.2F);
buffer2.put(3.9F);
buffer2.put(7.5F);
buffer2.put(5.8F);
buffer2.rewind();
System.out.println("The second FloatBuffer is: " + Arrays.toString(buffer2.array()));
int val = buffer1.compareTo(buffer2);
if (val == 0)
System.out.println("
Both the buffers are lexicographically equal");
else if (val > 0)
System.out.println("
The first buffer is lexicographically greater than the second buffer");
else
System.out.println("
The second buffer is lexicographically greater than the first buffer");
} catch (IllegalArgumentException e) {
System.out.println("Error!!! IllegalArgumentException");
} catch (ReadOnlyBufferException e) {
System.out.println("Error!!! ReadOnlyBufferException");
}
}
}
上述程序的输出如下 −
输出
The first FloatBuffer is: [4.5, 1.2, 3.9, 7.5, 5.8] The second FloatBuffer is: [4.5, 1.2, 3.9, 7.5, 5.8] Both the buffers are lexicographically equal
