我可以在 MySQL 查询中使用 BirthDate 列获取 Age 吗?
mysqlmysqli database更新于 2023/11/26 19:48:00
要在 MySQL 查询中使用 BirthDate 列获取 Age，您可以使用 datediff()。让我们首先创建一个表:
mysql> create table DemoTable ( Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, DateOfBirth date ); Query OK, 0 rows affected (1.46 sec)
下面是使用 insert 命令在表中插入一些记录的查询:
mysql> insert into DemoTable(DateOfBirth) values('2010-01-21');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable(DateOfBirth) values('1993-04-02');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable(DateOfBirth) values('1999-12-01');
Query OK, 1 row affected (1.53 sec)
mysql> insert into DemoTable(DateOfBirth) values('1998-11-16');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable(DateOfBirth) values('2004-03-19');
Query OK, 1 row affected (0.11 sec)
以下是使用 select 命令显示表中记录的查询:
mysql> select *from DemoTable;
这将产生以下输出:
+----+-------------+ | Id | DateOfBirth | +----+-------------+ | 1 | 2010-01-21 | | 2 | 1993-04-02 | | 3 | 1999-12-01 | | 4 | 1998-11-16 | | 5 | 2004-03-19 | +----+-------------+ 5 rows in set (0.00 sec)
现在让我们使用 DATEDIFF() 方法通过出生日期列获取年龄:
mysql> select cast(DATEDIFF(curdate(),DateOfBirth) / 365.25 AS UNSIGNED) AS AGE from DemoTable;
这将产生以下输出:
+------+ | AGE | +------+ | 9 | | 26 | | 19 | | 20 | | 15 | +------+ 5 rows in set (0.00 sec)
现在让我们编写一个查询来获取年龄在 20 到 26 岁之间的 DOB 和 ID:
mysql> SELECT *FROM DemoTable WHERE YEAR(CURDATE())-YEAR(DateOfBirth) BETWEEN 20 AND 26;
这将产生以下输出:
+----+-------------+ | Id | DateOfBirth | +----+-------------+ | 2 | 1993-04-02 | | 3 | 1999-12-01 | | 4 | 1998-11-16 | +----+-------------+ 3 rows in set (0.00 sec)
